(2x+3)(x^2+3x-10)=0

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Solution for (2x+3)(x^2+3x-10)=0 equation: 


Simplifying
(2x + 3)(x2 + 3x + -10) = 0

Reorder the terms:
(3 + 2x)(x2 + 3x + -10) = 0

Reorder the terms:
(3 + 2x)(-10 + 3x + x2) = 0

Multiply (3 + 2x) * (-10 + 3x + x2)
(3(-10 + 3x + x2) + 2x * (-10 + 3x + x2)) = 0
((-10 * 3 + 3x * 3 + x2 * 3) + 2x * (-10 + 3x + x2)) = 0
((-30 + 9x + 3x2) + 2x * (-10 + 3x + x2)) = 0
(-30 + 9x + 3x2 + (-10 * 2x + 3x * 2x + x2 * 2x)) = 0
(-30 + 9x + 3x2 + (-20x + 6x2 + 2x3)) = 0

Reorder the terms:
(-30 + 9x + -20x + 3x2 + 6x2 + 2x3) = 0

Combine like terms: 9x + -20x = -11x
(-30 + -11x + 3x2 + 6x2 + 2x3) = 0

Combine like terms: 3x2 + 6x2 = 9x2
(-30 + -11x + 9x2 + 2x3) = 0

Solving
-30 + -11x + 9x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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